two forces act on a hook. the magnitude are F1=300N toward the positive x-axis and F2=125N at a 48 degree angle to the x-axis. find the direction and the magnitude of the resultant force ?
Horizontal components: F1x = 300 F2x = 125 * cos (48) = 83.64132579 horizontal net force: Fx = 83.64132579 + 300 Fx = 383.6413258 N Vertical components: F2y = 125 * sine (48) = 92.89310318 vertical net force: Fy = 92.89310318 Magnitude of the resulting force: F = root ((Fx) ^ 2 + (Fy) ^ 2) F = root ((383.6413258) ^ 2 + (92.89310318) ^ 2) F = 125 Angle: theta = Atan (Fy / Fx) theta = Atan (92.89310318 / 383.6413258) theta = 13.61 degrees Answer: The direction and the magnitude of the resultant force are: F = 125 N theta = 13.61 degrees
