Since they are independent events to find the probability of both is P(A) * P(B)
P(A) = P(Heads) = [tex] \frac{1}{2} [/tex]
P(B) = P(Roll ≥ 4) = [tex] \frac{3}{6} = \frac{1}{2} [/tex]
Now multiply those fractions together
[tex] \frac{1}{2} * \frac{1}{2} = \frac{1}{4} [/tex] = P(Heads & ≥ 4)
