Let the 3 consecutive positive integers be x, x+1, x+2. The product of the smallest and largest: x(x+2), is 27 more than 3 times the median integer, the one in the middle, which is x+1. The equation will be: x(x+2) = 27+3(x+1) x^2 + 2x = 3x + 30 x^2 - x - 30 = 0 (x - 6)(x + 5) = 0 x = 6 (we don't consider x = -5 since the integers must be positive) x+1 = 7 x+2 = 8 So the consecutive integers are 6, 7, 8.
