No no need to take out the 2
You can factor this by using the ac method
2x^2 + 3x - 5 = 0
multiplying the first and last coefficients 2 * -5 = -10
Now we want to get 2 factors of -10 which will give us +3 when added:-
+5 and -2 seem ok so we write:-
2x^2 - 2x + 5x - 5 = 0
2x(x - 1) + 5 (x - 1) =0
(2x + 5)(x - 1) = 0
Solution is x = -5/2 and x = 1
