Answer:
[tex]y^{22/15}[/tex] or [tex]y^{1\frac{7}{15}}[/tex]
Step-by-step explanation:
Since the expression is y^(4/5)*y^(2/3), we have to add the powers.
4/5+2/3=12/15+10/15=22/15=1 7/15.
So it is [tex]y^{22/15}[/tex] or [tex]y^{1\frac{7}{15}}[/tex]
