The value of x in the equation e^2x = e^7x−5 is 1
How to solve for x in the equation?
The equation is given as:
e^2x = e^7x−5.
Next, we compare the exponents
2x = 7x - 5
Evaluate the like terms
-5x = -5
Divide by -5
x = 1
Hence, the value of x in the equation e^2x = e^7x−5 is 1
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