Answer:
5, 6, 7
Step-by-step explanation:
let the 3 consecutive integers be n , n + 1 , n + 2 , then
n(n + 2) = n+ 1 + 29
n² + 2n = n + 30 ( subtract n + 30 from both sides )
n² + n - 30 = 0 ← in standard form
(n + 6)(n - 5) = 0 ← in factored form
equate each factor to zero and solve for n
n + 6 = 0 ⇒ n = - 6
n - 5 = 0 ⇒ n = 5
n > 0 , then n = 5
the 3 integers are 5, 5 + 1, 5 + 2 , that is
5, 6, 7
