Answer:
[tex]y = e^{x^2 - 3x}\\\\\\Let \ u = x^2 - 3x\\\\y = e^u\\\\\frac{dy}{du} = e^u\\\\\frac{du}{dx} = 2x - 3\\\\y' = \frac{dy}{dx} = \frac{dy}{du} *\frac{du}{dx} = e^u * (2x -3)\\\\Substitute \ u = x^2 -3\\\\y' = (2x -3)e^{x^2-3x}\\\\option A[/tex]
