Answer:
2
Step-by-step explanation:
Given data
We have the function p(x)=(x-1)(x+1)
Let us find
p(2), p(1), and p(0)
p(2)= (2-1)(2+1)
p(2)= (1)(3)
p(2)= 3
P(1)= (1-1)(1+1)
p(1)= 0*1
P(1)= 0
p(0)= (0-1)(0+1)
p(0)= 1
Hence , p(2)+p(1)-p(0)
=3+0-1
=3-1
=2
