Answer:
B
Step-by-step explanation:
[tex]\dfrac{x}{3}+\dfrac{x}{7}<2[/tex]
Since the least common multiple of 3 and 7 is 21, multiply both sides by 21:
[tex]7x+3x<42 \\\\10x<42[/tex]
Divide both sides by 10 to isolate x:
[tex]x<\dfrac{42}{10}\\\\\\x<\dfrac{21}{5}[/tex]
Therefore, the correct answer is choice B. Hope this helps!
