Answer:
[tex]x\le 3[/tex]
Step-by-step explanation:
[tex]2(4+2x)\ge 5x+5[/tex]
[tex]2(4)+2(2x)\ge 5x+5[/tex]
[tex]8+4x\ge 5x+5[/tex]
[tex]8-5\ge 5x-4x[/tex]
[tex]3\ge 1x[/tex]
[tex]x \leqslant 3[/tex]
Third answer is correct.
[tex]2(4 + 2x) \geqslant 5x + 5 \\ 8 + 4x \geqslant 5x + 5 \\ 8 - 5 \geqslant 5x - 4x \\ = 3 \geqslant x[/tex]
hope this helps you
