Answer:
1 , 29/11
Step-by-step explanation:
3x+y = 10 ....(1)
2x² +y² = 19 ....(2)
3x+y= 10
y = 10-3x
substituting the value of y in 2nd equation
2x² + y² = 19
2x² + (10-3x)² = 19
2x² + 100 + 9x² - 60x -19 = 0
11x² - 60x +81 = 0
11x² - 33x - 27x + 81 = 0
11x( x-3) - 27(x-3) = 0
(x-3)(11x-27) = 0
x = 3, 27/11
substituting x value on first equation
x= 3 x= 27/11
y= 10-3(3) y= 10 - 81/11
= 10-9 = (110-81)/11
= 1 = 29/11
Hope it helps...
