First and second options are correct answers
Answer:
[tex] m\angle QRT = 90°\\
m\angle QRT =m\angle SRT[/tex]
Step-by-step explanation:
[tex] \triangle QST\: is \:an \:isosceles \:\triangle\\
ST \cong QT ... (GIVEN) \\
\overline{RT} \: bisects \: \angle T\\
\therefore TR \perp SQ\\
(By\: angle \: bisector \: postulate\: of\: an\:\\ isosceles\:\triangle) \\
\therefore m\angle QRT =m\angle SRT= 90°\\[/tex]
