Answer:
see below
Step-by-step explanation:
The fundamental rule of calculus tells you that for ...
[tex]\displaystyle f(x)=\int^{a(x)}_b {u(t)} \, dt \\\\f'(x)=u(a(x))a'(x)-u(b(x))b'(x)[/tex]
Then, for the specific case in this problem, we have ...
a(x) = x^2; a'(x) = 2x
b(x) = 1; b'(x) = 0
f'(x) = sin(x^2)/x^2·(2x)
f'(x) = 2sin(x^2)/x . . . . . matches choice D
