Answer:
[tex]x \in \varnothing[/tex]
Step-by-step explanation:
[tex]3x^{2} -5x+4=0\\ \Delta = \frac{-5^{2\pm \sqrt{5x^{2} -48} } }{6} =\frac{25\pm \sqrt{-23}}{6} \\ \Rightarrow x \in \varnothing \:(can't\: take\: square\: root\: of\: negative\: number)[/tex]
