Answer:
Heat loss is -7871.5J
Explanation:
Mass = 692g
Initial temperature (T1) = 176°C
Final temperature (T2) = 85°C
Specific heat capacity of Al = 0.125J/g°C
Heat energy = ?
Q = mc∇t
Q = heat energy
M = mass of substance
C = specific heat capacity of substance
∇t = change in temperature of substance = T2 - T1
Q = mc∇t
Q = 692 × 0.125 × (85 - 176)
Q = 86.5 × -91
Q = -7871.5J
The heat loss is -7871.5J or -7.87kJ
