Answer:
Explanation:
We shall apply gas law equation
[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]
P₁ = 221 X 10³
V₁ = 255 L
T₁ = 273 + 125
= 398 K
P₂ = 1.01 x 10⁵ ( Standard pressure )
V₂ = ?
T₂= 273 K ( standard temperature is 0 degree )
Putting the values above in the gas equation
[tex]\frac{221000\times 255}{398} =\frac{101000V_2}{273}[/tex]
V₂ = 382.73 L .
