Answer:
(6, 1)
Step-by-step explanation:
[tex] {x}^{2} + {y}^{2} - 12x - 2y + 12 = 0 \\ equating \: it \: with \\ {x}^{2} + {y}^{2} + 2gx + 2fy + c= 0 \\we \: find \\ 2g = - 12 \implies \: g = - 6 \\ 2f = - 2 \implies \: f = - 1 \\ center \: of \: circle = ( - g \: \: - f) \\ center \: of \: circle = (6 \: \: 1)[/tex]
