Answer:
Step-by-step explanation:
Answer:
(f+g)(x)=3x^2+\frac{7}{3}x-8
Step-by-step explanation:
The given functions are:
f(x)=\frac{x}{3}-2 and g(x)=3x^2+2x-6
Now, (f+g)(x)=f(x)+g(x)
therefore, (f+g)(x)=\frac{x}{3}-2+3x^2+2x-6
=3x^2+2x+\frac{x}{3}-8
=\frac{9x^2+6x+x-24}{3}
=\frac{9x^2+7x-24}{3}
=3x^2+\frac{7}{3}x-8
Thus, (f+g)(x)=3x^2+\frac{7}{3}x-8
