Answer:
[tex]p_2 = 1.76 atm[/tex]
Explanation:
given data:
v_1 = 2.37 L
v_2 = 1.68 L
p_1 =1.15 atm
p_2 = ?
t_1 = 280 K
t_2 = 304 K
from Gas Law Equation
, WE HAVE
[tex]\frac{p_1 v_1}{t_1} =\frac{p_2 v_2}{t_2}[/tex]
Putting the values
[tex]\frac{1.15*2.37}{280} =\frac{p_2 *1.68}{304}[/tex]
[tex]9.733*10^{-3} = \frac{p_2 *1.68}{304}[/tex]
[tex]9.733*10^{-3}*304 = p_2*1.68[/tex]
[tex]\frac{9.733*10^{-3}*304}{1.68} =p_2[/tex]
[tex]p_2= 1.76 atm[/tex]
