Respuesta :

evgeniylevi

Try this option:

for x²+9x+2=0 D=81-8=73

[tex]\left \ [ {{x= }\frac{-9- \sqrt{73}}{2}  \atop {x=}\frac{-9+ \sqrt{73}}{2} } \right \ => \left \ [{{x=-8.772} \atop {x=-0.228}[/tex]

answer: x≈ -8.772 or x= -0.228

Otras preguntas