First, find the slope (m) = [tex] \frac{y2 - y1}{x2 - x1} [/tex] = [tex] \frac{5 - 6}{1 - 4} [/tex] = [tex] \frac{-1}{-3} [/tex] = [tex] \frac{1}{3} [/tex]
Now plug in ONE of the points and the slope into the point-slope equation:
y - y₁ = m(x - x₁); where (x₁, y₁) is the chosen point.
y - 5 = [tex] \frac{1}{3} [/tex](x - 1) (I used (1,5) as the chosen point)
3(y - 5) = x - 1
3y - 15 = x - 1
3y -14 = x
-14 = x - 3y → x - 3y = -14
Answer: x - 3y = -14
