0.001 mol/L. The concentration of an aqueous solution of NaOH with a pH
of 11 is 0.001 mol/L
Step 1. Calculate the pOH of the solution
pOH = 14.00 – pH = 14.00 -11 = 3
Step 2. Calculate the concentration of NaOH
[NaOH] = [OH^(-)] = 10^(-pOH) mol/L = 10^(-3) mol/L = 0.001 mol/L
